32x^2-968=0

Solution for 32x^2-968=0 equation:

32x^2-968=0

a = 32; b = 0; c = -968;
Δ = b2-4ac
Δ = 02-4·32·(-968)
Δ = 123904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{123904}=352$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-352}{2*32}=\frac{-352}{64}
=-5+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+352}{2*32}=\frac{352}{64}
=5+1/2
$